Depending on the exact voltage they drop (probably around 4V), I'd wire them in series in twos or threes with a series resistor to drop the rest (the larger the difference between sum of diode forward voltages and the [varying] supply voltage, the better consistency of current through the LEDs as the supply voltage varies. So I'd only use 2 in series). Then add up such sets in parallell until you have the wanted number of LEDs. Forward current through the LEDs is typically in the 20 to 30mA range.
Resistor value = (13.5 - (N * V_forward)) / I_forward
Resistor power handling capacity = (14.5 - (N * V_forward))^2 / Resistor value
I used 13.5 as an average of supply voltage, but 14.5 (max) when calculating the power handling requirement. I also wouldn't go with absolute max forward current but rather the typical value.
/Michael
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/Michael