Measure the voltage across resistor in series with either line. I'd be looking at something like 0.47 or 1ohm. Then calculate from I = V/R (in amps, volts and ohms)
[Shonky knows this already, but perhaps others here don't]
That is exactly what the 10A range on the (cheapo) meters I have here does. The red probe plugs into a special socket that has a sub-ohm resistor in series with the black probe, and it measures the drop across it to calculate the current.
The regular red probe input is fused for less than 1A.. hopefully the fuse might blow rather than the meter frying, but no guarantees on that.
Cheers
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